Thu Jul 14, 2005 6:23 am
Thu Jul 14, 2005 12:33 pm
Thu Jul 14, 2005 12:48 pm
Thu Jul 14, 2005 1:01 pm
Thu Jul 14, 2005 1:14 pm
Thu Jul 14, 2005 1:56 pm
the_dog_god wrote:Fine then...breeding place for bent or misleading truths and facts, weirdos and pedantic forumers...
Thu Jul 14, 2005 5:21 pm
Trick wrote:Anyway I liked it (before all the pedantry) and a lot of people I know got a good laugh from it. I'm guessing I am allowed to enjoy it for the fun it is supposed to be
Thu Jul 14, 2005 7:44 pm
Trick wrote:(*Dranzer*) wrote:Its 1/7.
Pick any day.
That day has 1 out of 7 chances to be picked again.
Each day has a 1/7 chance.
7/49= 1/7.
You only calculate probabilities like this if you're saying "what is the probability that one president or the other dies on a Friday" not "what is the probability that both presidents die on a Friday".
An addition of probabilities like that is an AND calculation, so you use multiplication... 1\7 * 1\7 = 1\49 like LaceyJade said.
...good grief, I remembered maths :0
Thu Jul 14, 2005 9:12 pm
M. Bison wrote:The chance of two people dying on the same day is 1/7. There is no probability involving the day of Lincoln's death, as it does not matter. To fulfill the condition, Kennedy has to die the same day Lincoln did. And he had a 1/7 chance of doing so.
Thu Jul 14, 2005 9:27 pm
Trick wrote:M. Bison wrote:The chance of two people dying on the same day is 1/7. There is no probability involving the day of Lincoln's death, as it does not matter. To fulfill the condition, Kennedy has to die the same day Lincoln did. And he had a 1/7 chance of doing so.
Wouldn't that be the probability that a second president dies on a Friday, rather than the probability that two die on a Friday? I was under the impression it was the same as working the probability of rolling two sixes. Or would that be if it was the same Friday....meh, don't look at me, I hated stats
Thu Jul 14, 2005 9:29 pm
M. Bison wrote:Trick wrote:(*Dranzer*) wrote:Its 1/7.
Pick any day.
That day has 1 out of 7 chances to be picked again.
Each day has a 1/7 chance.
7/49= 1/7.
You only calculate probabilities like this if you're saying "what is the probability that one president or the other dies on a Friday" not "what is the probability that both presidents die on a Friday".
An addition of probabilities like that is an AND calculation, so you use multiplication... 1\7 * 1\7 = 1\49 like LaceyJade said.
...good grief, I remembered maths :0
The chance of two people dying on the same day is 1/7. There is no probability involving the day of Lincoln's death, as it does not matter. To fulfill the condition, Kennedy has to die the same day Lincoln did. And he had a 1/7 chance of doing so.
Thu Jul 14, 2005 9:31 pm
LaceyJade wrote:M. Bison wrote:Trick wrote:(*Dranzer*) wrote:Its 1/7.
Pick any day.
That day has 1 out of 7 chances to be picked again.
Each day has a 1/7 chance.
7/49= 1/7.
You only calculate probabilities like this if you're saying "what is the probability that one president or the other dies on a Friday" not "what is the probability that both presidents die on a Friday".
An addition of probabilities like that is an AND calculation, so you use multiplication... 1\7 * 1\7 = 1\49 like LaceyJade said.
...good grief, I remembered maths :0
The chance of two people dying on the same day is 1/7. There is no probability involving the day of Lincoln's death, as it does not matter. To fulfill the condition, Kennedy has to die the same day Lincoln did. And he had a 1/7 chance of doing so.
No, because Lincoln had to die on the same day Kennedy died, too. Since there are 7 days in the week, and Lincoln died on one of them. So you get 1/7 from there. The probability of Kennedy dying on ANY day is also 1/7. If you multiply them together, you get 1/49, which is the probability of both dying on the same day.
Thu Jul 14, 2005 9:33 pm
o_0 wrote:LaceyJade wrote:M. Bison wrote:Trick wrote:(*Dranzer*) wrote:Its 1/7.
Pick any day.
That day has 1 out of 7 chances to be picked again.
Each day has a 1/7 chance.
7/49= 1/7.
You only calculate probabilities like this if you're saying "what is the probability that one president or the other dies on a Friday" not "what is the probability that both presidents die on a Friday".
An addition of probabilities like that is an AND calculation, so you use multiplication... 1\7 * 1\7 = 1\49 like LaceyJade said.
...good grief, I remembered maths :0
The chance of two people dying on the same day is 1/7. There is no probability involving the day of Lincoln's death, as it does not matter. To fulfill the condition, Kennedy has to die the same day Lincoln did. And he had a 1/7 chance of doing so.
No, because Lincoln had to die on the same day Kennedy died, too. Since there are 7 days in the week, and Lincoln died on one of them. So you get 1/7 from there. The probability of Kennedy dying on ANY day is also 1/7. If you multiply them together, you get 1/49, which is the probability of both dying on the same day.
But Lincoln could have died on any day, as he did not need to fulfill a requirement set before him, like Kennedy did. o.o
Thu Jul 14, 2005 9:51 pm
Thu Jul 14, 2005 10:07 pm
LaceyJade wrote:o_0 wrote:LaceyJade wrote:M. Bison wrote:Trick wrote:(*Dranzer*) wrote:Its 1/7.
Pick any day.
That day has 1 out of 7 chances to be picked again.
Each day has a 1/7 chance.
7/49= 1/7.
You only calculate probabilities like this if you're saying "what is the probability that one president or the other dies on a Friday" not "what is the probability that both presidents die on a Friday".
An addition of probabilities like that is an AND calculation, so you use multiplication... 1\7 * 1\7 = 1\49 like LaceyJade said.
...good grief, I remembered maths :0
The chance of two people dying on the same day is 1/7. There is no probability involving the day of Lincoln's death, as it does not matter. To fulfill the condition, Kennedy has to die the same day Lincoln did. And he had a 1/7 chance of doing so.
No, because Lincoln had to die on the same day Kennedy died, too. Since there are 7 days in the week, and Lincoln died on one of them. So you get 1/7 from there. The probability of Kennedy dying on ANY day is also 1/7. If you multiply them together, you get 1/49, which is the probability of both dying on the same day.
But Lincoln could have died on any day, as he did not need to fulfill a requirement set before him, like Kennedy did. o.o
If Kennedy had to die on the same day Lincoln did, then Lincoln had to have died on the same day Kennedy did, no? AB = BA.