Dice Roll Thread

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Pickles
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Re: Dice Roll Thread

#46 Post by Pickles »

Hm. Just testing... :P
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Re: Dice Roll Thread

#47 Post by Ammer »


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Re: Dice Roll Thread

#48 Post by pipsqueeek »

Siniri wrote:
Jas O'Lantern wrote:I wonder how much variety this will give.
The standard deviation for a 10-sided die is 2.872281323.
Variance=8.25.
Range=[1,10]. :P

I only bothered because I still had the SD calculated from my earlier experiment...

/procrastination
The distribution wouldn't be normal though(we hope), so standard deviation wouldn't really be relevant...
Unless you mean for multiple dice. But then it'd be different for different numbers of dice.

Just because...




It amuses me that you can roll dice that can't physically exist :P.
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Re: Dice Roll Thread

#49 Post by Siniri »

pipsqueeek wrote:
Siniri wrote:
Jas O'Lantern wrote:I wonder how much variety this will give.
The standard deviation for a 10-sided die is 2.872281323.
Variance=8.25.
Range=[1,10]. :P

I only bothered because I still had the SD calculated from my earlier experiment...

/procrastination
The distribution wouldn't be normal though(we hope), so standard deviation wouldn't really be relevant...
Unless you mean for multiple dice. But then it'd be different for different numbers of dice.
Right. I didn't use the normal distribution to calculate the SD. Every distribution has a variance, and thus a SD (which is the square root of the variance). The variance does change with the number of sides on the die, of course. During my experiment, I relied on the Central Limit Theorem given my large number of trials (and thus I used z-tests to determine the p-values). But the SD's I used for each die were not based on the normal distribution. Admittedly, I looked the formula up on-line instead of referring to my old textbooks, but it gelled with the one in my memory -- and it gave the proper variance for a two-sided die, which is just a binomial distribution. FYI, for a discrete random variable, the variance is the sum of {(probability of outcome i) times [(<value of outcome i> minus mean) squared]}. So for a 2-sided die, it's 1/2 * [(1-1.5)^2 + (2-1.5)^2] (because the probability for each outcome is the same for a fair die, it can be pulled outside the summation) = 0.25.

Jas wondered about the variety that would be given by her roll -- and variance is a measure of how spread out a distribution is; I thought this might be what she meant by variety.
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Re: Dice Roll Thread

#50 Post by Light »

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Re: Dice Roll Thread

#51 Post by Xaidread »


A 95 out of 777 numbers... Interesting.
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Re: Dice Roll Thread

#52 Post by Combusken BG »








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Re: Dice Roll Thread

#53 Post by Siniri »


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Re: Dice Roll Thread

#54 Post by BeDeviled »



hmmm...
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Re: Dice Roll Thread

#55 Post by Regan »

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Re: Dice Roll Thread

#56 Post by Raz »


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By WisWis :3
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Re: Dice Roll Thread

#57 Post by Cerise »

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Re: Dice Roll Thread

#58 Post by Uncle Xyzzy »





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Re: Dice Roll Thread

#59 Post by Evil Stu Man »

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Re: Dice Roll Thread

#60 Post by lemonade »

I'm too old for this!
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